Задание № 1132

Выполните действия:

$\frac{(53\frac34+9\frac16)\ast1\frac15}{(10\frac3{10}\ast8\frac12)\ast\frac59}-\frac{(6\frac45-3\frac37)\ast5\frac56}{3\frac23-3\frac16}-29\frac56=\frac{(62+\frac{3\ast3+1\ast2}{12})\ast\frac65}{(2\frac3{10}-\frac12)\ast\frac59}-\frac{(3\frac45-\frac37)\ast\frac{35}6}{\frac23-\frac16}-29\frac56=\frac{62\frac{11}{12}\ast\frac65}{(1\frac{13}{10}-\frac5{10})\ast\frac59}-\frac{(3\frac{28}{35}-\frac{15}{35})\ast\frac{35}6}{\frac46-\frac16}-29\frac56=\frac{\frac{755}{12}\ast\frac65}{\frac{18}{10}\ast\frac59}-\frac{\frac{118}{35}\ast\frac{35}6}{\frac12}-29\frac56=\frac{\frac{151\ast5}{6\ast2}\ast\frac65}{\frac{9\ast2}{5\ast2}\ast\frac59}-\frac{\frac{59\ast2}{35}\ast\frac{35}{3\ast2}}{\frac12}-29\frac56=\frac{\frac{151}2}{\frac11}-\frac{\frac{59}3}{\frac12}-29\frac56=\frac{151}2-\frac{59}3\ast\frac21-29\frac56=\frac{151}2-\frac{118}3-29\frac56=75\frac12-39\frac13-29\frac56=36\frac12-\frac13-29\frac56=36\frac36-\frac26-29\frac56=36\frac16-29\frac56=7\frac16-\frac56=6\frac76-\frac56=6\frac26=6\frac13$

Задание № 1133

Выполните действия:

$\frac{(28:1\frac34+1\frac13:22+1\frac23\ast9\frac3{11}+4:1\frac12)\ast3\frac17}{67\frac17-47\ast\frac27}=\frac{(28:\frac74+\frac43:22+\frac53\ast\frac{102}{11}+4:\frac32)\ast\frac{22}7}{67\frac17-\frac{94}7}=\frac{(7\ast4\ast\frac47+\frac{2\ast2}3\ast\frac1{2\ast11}+\frac53\ast\frac{34\ast3}{11}+4\ast\frac23)\ast\frac{22}7}{67\frac17-13\frac37}=\frac{(16+\frac23\ast\frac1{11}+\frac51\ast\frac{34}{11}+\frac83)\ast\frac{22}7}{54\frac17-\frac37}=\frac{(16+\frac2{33}+\frac{170}{11}+\frac83)\ast\frac{22}7}{53\frac87-\frac37}=\frac{(16+\frac{2+170\ast3+8\ast11}{33})\ast\frac{22}7}{53\frac57}=\frac{(16+\frac{2+510+88}{33})\ast\frac{22}7}{\frac{376}7}=\frac{(16+\frac{600}{33})\ast\frac{22}7}{\frac{376}7}=\frac{(16\frac{600}{33})\ast\frac{22}7}{\frac{376}7}=\frac{\frac{1128}{33}\ast\frac{22}7}{\frac{376}7}=\frac{1128}{33}\ast\frac{22}7\ast\frac7{376}=\frac{376\ast3}{3\ast11}\ast\frac{2\ast11}7\ast\frac7{376}=2$

Задание № 1134

Выполните действия:

$\frac{((6\frac23+2\frac4{15}+5\frac12):\frac1{15}-30:\frac5{28}):2\frac34}{(5\ast\frac45-\frac35\ast\frac5{22}):42\frac12}=\frac{((13+\frac{2\ast10+4\ast2+1\ast15}{30})\ast\frac{15}1-5\ast6\ast\frac{28}5):\frac{11}4}{(4-\frac32):\frac{85}2}=\frac{((13\ast15+\frac{15\ast(20+8+15)}{2\ast15})-6\ast28)\ast\frac4{11}}{(3\frac{22}{22}-\frac3{22}):\frac{85}2}=\frac{((195+\frac{43}2)-168)\ast\frac4{11}}{3\frac{19}{22}:\frac{85}2}=\frac{(195\frac{43}2-168)\ast\frac4{11}}{\frac{85}{22}\ast\frac2{85}}=\frac{27\frac{43}2\ast\frac4{11}}{\frac{85}{11\ast2}\ast\frac2{85}}=\frac{\frac{97}2\ast\frac4{11}}{\frac1{11}}=\frac{97}2\ast\frac4{11}\ast\frac{11}1=97\ast2=194$

Задание № 1135

Выполните действия:

$\frac{(\frac{23}{36}+\frac{31}{63}-(\frac34+\frac5{21}))\ast(48:(\frac35:\frac78))}{(\frac{19}{26}+\frac{14}{39}-\frac16)\ast(54\frac16:(8\frac47:\frac{12}{35}))}=\frac{(\frac{23\ast7+31\ast4}{252}-\frac{3\ast21+5\ast4}{84})\ast(48:(\frac35\ast\frac87))}{\frac{19\ast3+14\ast2-1\ast13}{78}\ast(\frac{325}6:(\frac{60}7\ast\frac{35}{12}))}=\frac{(\frac{161+124}{252}-\frac{63+20}{84})\ast(48:\frac{24}{35})}{\frac{57+28-13}{78}\ast(\frac{325}6:(\frac{12\ast5}7\ast\frac{5\ast7}{12}))}=\frac{(\frac{285}{252}-\frac{83}{84})\ast(\frac{24\ast2}1\ast\frac{35}{24})}{\frac{72}{78}\ast(\frac{326}6:25)}=\frac{\frac{285-83\ast3}{252}\ast(2\ast35)}{\frac{12\ast6}{13\ast6}\ast(\frac{325}6:25)}=\frac{\frac{285-249}{252}\ast70}{\frac{12}{13}\ast(\frac{13\ast25}6\ast\frac1{25})}=\frac{\frac{36}{36\ast7}\ast7\ast10}{\frac{12}{13}\ast\frac{13}6}=\frac{10}2=5$

Задание № 1136

Выполните действия:

а) $(3\frac12:4\frac23+4\frac23:3\frac12)\ast4\frac45=(\frac72:\frac{14}3+\frac{14}3:\frac72)\ast\frac{24}5=(\frac72\ast\frac3{14}+\frac{14}3\ast\frac27)\ast\frac{24}5=\frac72\ast\frac3{14}\ast\frac{24}5+\frac{14}3\ast\frac27\ast\frac{24}5=\frac72\ast\frac3{7\ast2}\ast\frac{2\ast12}5+\frac{7\ast2}3\ast\frac27\ast\frac{3\ast8}5=\frac{3\ast6}5+\frac{4\ast8}5=\frac{18+32}5=\frac{50}5=10$

б) $3\frac18:((4\frac5{12}-3\frac{13}{24})\ast\frac47+(3\frac1{18}-2\frac7{12})\ast1\frac{10}{17})=\frac{25}8:((1\frac5{12}-\frac{13}{24})\ast\frac47+(1\frac1{18}-\frac7{12})\ast\frac{27}{17})=\frac{25}8:((\frac{34}{24}-\frac{13}{24})\ast\frac47+(\frac{38}{36}-\frac{21}{36})\ast\frac{27}{17})=\frac{25}8:(\frac{21}{24}\ast\frac47+\frac{17}{36}\ast\frac{27}{17})=\frac{25}8:(\frac{3\ast7}{4\ast6}\ast\frac47+\frac{17}{9\ast4}\ast\frac{3\ast9}{17})=\frac{25}8:(\frac36+\frac34)=\frac{25}8:\frac{3\ast2+3\ast3}{12}=\frac{25}8\ast\frac{6+9}{12}=\frac{25}8\ast\frac{12}{15}=\frac{5\ast5}{4\ast2}\ast\frac{4\ast3}{5\ast3}=\frac52=2\frac12$

в) $2\frac34:((4\frac57-1\frac{11}{14})\ast4\frac23+(3\frac29-1\frac56)\ast\frac{18}{25})=\frac{11}4:((3\frac57-\frac{11}{14})\ast\frac{14}3+(2\frac29-\frac56)\ast\frac{18}{25})=\frac{11}4:((2\frac{24}{14}-\frac{11}{14})\ast\frac{14}3+(1\frac{22}{18}-\frac{15}{18})\ast\frac{18}{25})=\frac{11}4:(2\frac{13}{14}\ast\frac{14}3+1\frac7{18}\ast\frac{18}{25})=\frac{11}4:(\frac{41}{14}\ast\frac{14}3+\frac{25}{18}\ast\frac{18}{25})=\frac{11}4:(\frac{41}3+1)=\frac{11}4:\frac{44}3=\frac{11}4\ast\frac3{44}=\frac{11}4\ast\frac3{4\ast11}=\frac3{16}$

г) $(15:3\frac34-(10\frac12:1\frac12)\ast\frac3{14}):(1\frac{23}{52}-1\frac14)=(15:\frac{15}4-(\frac{21}2:\frac32)\ast\frac3{14}):(\frac{75}{52}-\frac54)=(15\ast\frac4{15}-(\frac{21}2\ast\frac23)\ast\frac3{14}):\frac{75-5\ast13}{52}=(4-7\ast\frac3{14}):\frac{75-65}{52}=(4-\frac32):\frac{10}{52}=(4-1\frac12)\ast\frac{52}{10}=(3-\frac12)\ast\frac{26\ast2}{5\ast2}=2\frac12\ast\frac{26}5=\frac52\ast\frac{26}5=13$

д) $\frac{(\frac7{15}+\frac{14}{45}+\frac29)\ast10\frac13-1\frac1{11}\ast(2\frac23-1\frac34)}{(\frac37-\frac14):\frac3{28}-1}=\frac{\frac{7\ast3+14+2\ast5}{45}\ast10\frac13-\frac{12}{11}\ast(1\frac23-\frac34)}{\frac{3\ast4-1\ast7}{28}:\frac3{28}-1}=\frac{\frac{21+14+10}{42}\ast10\frac13-\frac{12}{11}\ast(\frac{20}{12}-\frac9{12})}{\frac{12-7}{28}\ast\frac{28}3-1}=\frac{\frac{45}{45}\ast\frac{31}3-\frac{12}{11}\ast\frac{11}{12}}{\frac5{28}\ast\frac{28}3-1}=\frac{10\frac13-1}{\frac53-1}=\frac{9\frac13}{1\frac23-1}=\frac{9\frac13}{\frac23}=\frac{28}3\ast\frac32=14$

е) $\frac{15:\frac5{18}:3\frac38\ast(\frac1{16}+\frac{11}{36}+\frac5{48}+\frac5{18})}{(11\frac5{11}-8\frac{21}{22}):1\frac23}=\frac{15\ast\frac{18}5:\frac{27}8\ast((\frac1{16}+\frac5{48})+(\frac{11}{36}+\frac5{18}))}{(3\frac5{11}-\frac{21}{22}):\frac53}=\frac{15\ast\frac{18}5\ast\frac8{27}\ast(\frac{1\ast3+5}{48}+\frac{11+5\ast2}{36})}{(2\frac{32}{22}-\frac{21}{22}):\frac53}=\frac{3\ast5\ast\frac{2\ast9}5\ast\frac8{3\ast9}\ast(\frac{3+5}{48}+\frac{11+10}{36})}{2\frac{11}{22}:\frac53}=\frac{2\ast8\ast(\frac8{48}+\frac{21}{36})}{\frac{55}{22}:\frac53}=\frac{16\ast(\frac16+\frac7{12})}{\frac52\ast\frac35}=\frac{16\ast\frac{1\ast2+7}{12}}{\frac32}=\frac{4\ast4\ast\frac{3\ast3}{3\ast4}}{\frac32}=12\ast\frac23=4\ast2=8$